[{"data":1,"prerenderedAt":-1},["ShallowReactive",2],{"public-settings":3,"content:materi:demo-materi-fisika-sma-1":11,"public-catalog":158},{"features.tutoring.enabled":4,"sections.subjects.enabled":5,"sections.pricing.enabled":5,"sections.teachers.enabled":5,"sections.testimonials.enabled":4,"sections.faqs.enabled":5,"bankSoal.enabled":5,"site.maintenance":4,"whatsapp.number":6,"brand.name":7,"brand.tagline":8,"contact.email":9,"contact.address":10},false,true,"6285156084435","MyFismat","Platform belajar Matematika, Fisika, dan Pemrograman untuk SD, SMP, SMA, dan Kuliah","support@myfismat.com","Indonesia",{"id":12,"type":13,"slug":14,"title":15,"excerpt":16,"coverUrl":17,"status":18,"publishedAt":19,"featured":5,"subjectId":20,"blocks":21,"seoTitle":17,"seoDescription":17,"readingMinutes":61,"order":62,"createdAt":63,"updatedAt":63,"subject":64,"levels":69,"topics":74,"tags":78,"author":17,"resolved":79,"related":88},"demo-v2-m-fisika-sma-1","MATERIAL","demo-materi-fisika-sma-1","Hukum II Newton dan Gesekan pada Bidang Datar","Membuat diagram gaya, menentukan resultan, dan membedakan gesekan statis dari gesekan kinetik.",null,"PUBLISHED","2026-10-08T10:03:56.818Z","cmuzbyhdq000571r9nsdk6scx",[22,27,31,35,39,43,47,51,55],{"id":23,"data":24,"type":26},"section-1",{"markdown":25},"## Tujuan dan prasyarat\n\nKamu akan membuat diagram benda bebas, menerapkan hukum II Newton pada tiap arah, dan memutuskan model gesekan yang tepat. Prasyaratnya adalah vektor satu dimensi, percepatan, serta operasi aljabar. Kita memakai kerangka acuan inersial, benda bermassa tetap, bidang datar, dan tarikan mendatar. Gunakan g = 10 m\u002Fs² dalam contoh. Hambatan udara diabaikan.\n","text",{"id":28,"data":29,"type":26},"section-2",{"markdown":30},"## Pilih benda dan gambarkan semua gaya\n\nHukum II Newton berbunyi $\\sum\\vec F=m\\vec a$. Tanda sigma berarti jumlah seluruh gaya eksternal pada benda yang dipilih. Massa m dalam kg menyatakan inersia, sedangkan percepatan a dalam m\u002Fs² menyatakan laju perubahan kecepatan. Gaya dalam newton mempunyai satuan kg·m\u002Fs². Resultan menentukan percepatan, bukan langsung menentukan kecepatan.\n\nUntuk balok di lantai, gambarkan berat $mg$ ke bawah, gaya normal N ke atas, gaya tarik horizontal, dan gesekan bila permukaannya memberikan gesekan. Gaya normal adalah gaya kontak tegak lurus permukaan; huruf N pada rumus bukan satuan newton, meskipun ditulis dengan huruf yang sama. Jika tidak ada percepatan vertikal dan tarikan mendatar, $N-mg=0$, sehingga $N=mg$. Persamaan ini tidak otomatis berlaku untuk tarikan miring, lift yang dipercepat, atau bidang miring.\n",{"id":32,"data":33,"type":26},"section-3",{"markdown":34},"## Dua model gesekan\n\nGesekan statis berlaku ketika permukaan tidak meluncur relatif. Besarnya menyesuaikan kebutuhan sampai batas $f_s\\leq\\mu_sN$. Simbol $\\mu_s$ adalah koefisien gesekan statis, tanpa satuan. Nilai $\\mu_sN$ adalah batas maksimum, bukan besar gesekan statis pada setiap keadaan. Jika gaya tarik kecil, gesekan dapat sama besar dengan gaya tarik sehingga balok tetap diam.\n\nSaat balok sudah meluncur, model sederhana memakai $f_k=\\mu_kN$. Koefisien $\\mu_k$ juga tidak bersatuan. Gesekan kinetik berlawanan dengan gerak relatif pada permukaan. Model ini menganggap koefisien tetap pada kondisi yang dibahas; permukaan nyata dapat menunjukkan variasi. Jangan memakai kedua rumus sekaligus pada kontak yang sama tanpa menentukan apakah balok diam atau meluncur.\n",{"id":36,"data":37,"type":26},"section-4",{"markdown":38},"## Contoh 1: balok sedang meluncur\n\nBalok 5 kg meluncur ke kanan dan ditarik 30 N ke kanan. Koefisien kinetik 0,2. Langkah pertama, karena percepatan vertikal nol, $N=5(10)=50$ N. Langkah kedua, $f_k=0{,}2(50)=10$ N ke kiri. Langkah ketiga, resultan mendatar $30-10=20$ N, sehingga $a=20\u002F5=4$ m\u002Fs² ke kanan. Cek: $ma=5(4)=20$ N. Kelajuan akan bertambah karena kecepatan dan percepatan searah. Tanpa kecepatan awal serta waktu, kita belum dapat menentukan kelajuannya pada saat tertentu.\n",{"id":40,"data":41,"type":26},"section-5",{"markdown":42},"## Contoh 2: gaya tarik belum mengatasi gesekan statis\n\nBalok 4 kg mula-mula diam dengan $\\mu_s=0{,}5$. Gaya tarik mendatar 12 N. Normal $N=4(10)=40$ N, sehingga batas statis $f_{s,\\max}=0{,}5(40)=20$ N. Agar tetap diam, dibutuhkan gesekan 12 N ke kiri. Karena 12 N lebih kecil daripada 20 N, gesekan tersebut tersedia dan $a=(12-12)\u002F4=0$. Cek hasil dengan membandingkan kebutuhan dan batas, bukan dengan mengurangkan gaya tarik dari batas maksimum. Menulis gesekan 20 N akan menghasilkan percepatan ke kiri tanpa sebab untuk balok diam ini.\n",{"id":44,"data":45,"type":26},"section-6",{"markdown":46},"## Kekeliruan umum\n\nBerat dan normal bekerja pada benda yang sama sehingga bukan pasangan aksi–reaksi. Pasangan reaksi gaya Bumi pada balok adalah gaya balok pada Bumi. Benda bergerak dengan kecepatan tetap memiliki resultan nol, tetapi masing-masing gaya dapat tetap ada. Percepatan negatif dapat berarti melambat atau bergerak makin cepat ke arah negatif, tergantung tanda kecepatan.\n",{"id":48,"data":49,"type":26},"section-7",{"markdown":50},"## Ringkasan dan cek mandiri\n\nPilih benda, tentukan arah positif, hitung normal, pilih jenis gesekan, lalu pakai resultan. Untuk balok 2 kg meluncur ke kanan dengan gaya tarik 10 N dan gesekan 4 N, percepatannya 3 m\u002Fs² ke kanan. Jelaskan mengapa menghitung 10\u002F2 saja menghasilkan jawaban yang terlalu besar.",{"id":52,"data":53,"type":26},"sources",{"markdown":54},"## Sumber belajar\n\n- [OpenStax College Physics 2e — Newton’s Second Law of Motion](https:\u002F\u002Fopenstax.org\u002Fbooks\u002Fcollege-physics-2e\u002Fpages\u002F4-3-newtons-second-law-of-motion-concept-of-a-system)\n- [OpenStax College Physics 2e — Friction](https:\u002F\u002Fopenstax.org\u002Fbooks\u002Fcollege-physics-2e\u002Fpages\u002F5-1-friction)\n\nPenjelasan dan contoh disusun ulang untuk materi ini; sumber dapat dibuka untuk belajar lebih lanjut.",{"id":56,"data":57,"type":60},"practice",{"title":58,"questionSetId":59},"Cek pemahaman: Hukum II Newton dan Gesekan pada Bidang 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Khusus — Kelas 12.","2026-10-08T09:24:41.291Z",{"id":477,"subjectId":20,"levelId":71,"parentId":17,"slug":1748,"name":1749,"description":1750,"order":1751,"createdAt":1752,"updatedAt":1752},"gejala-kuantum","Gejala Kuantum","Gejala Kuantum — Kelas 12.",29,"2026-10-08T09:24:41.303Z",{"id":376,"subjectId":161,"levelId":71,"parentId":17,"slug":1754,"name":1755,"description":1756,"order":1751,"createdAt":1757,"updatedAt":1757},"penerapan-integral","Penerapan Integral","Penerapan Integral — Kelas 12 Lanjut.","2026-10-08T09:24:41.607Z",{"id":268,"subjectId":161,"levelId":71,"parentId":17,"slug":1759,"name":1760,"description":1761,"order":1762,"createdAt":1763,"updatedAt":1763},"analisis-data-peluang","Analisis Data & Peluang","Analisis Data & Peluang — Kelas 12 Lanjut.",30,"2026-10-08T09:24:41.611Z",{"id":412,"subjectId":20,"levelId":71,"parentId":17,"slug":1765,"name":1766,"description":1767,"order":1762,"createdAt":1768,"updatedAt":1768},"fisika-inti-dan-radioaktivitas","Fisika Inti dan Radioaktivitas","Fisika Inti dan Radioaktivitas — Kelas 12.","2026-10-08T09:24:41.318Z",{"id":1770,"subjectId":161,"levelId":71,"parentId":17,"slug":1771,"name":1772,"description":1773,"order":1774,"createdAt":1775,"updatedAt":1775},"cmuzbyhw700gw71r9o87lq7vd","logaritma","Logaritma","Logaritma — Kelas 12 Lanjut.",31,"2026-10-08T09:24:41.623Z",{"id":1777,"subjectId":161,"levelId":71,"parentId":17,"slug":1778,"name":1779,"description":1780,"order":1781,"createdAt":1782,"updatedAt":1782},"cmuzbyhw900gy71r9d9sjh9ie","program-linier","Program Linier","Program Linier — Kelas 12 Lanjut.",32,"2026-10-08T09:24:41.625Z",{"id":1784,"subjectId":161,"levelId":71,"parentId":17,"slug":1785,"name":1786,"description":1787,"order":1788,"createdAt":1789,"updatedAt":1789},"cmuzbyhwb00h071r97764r7hr","bangun-ruang","Bangun Ruang","Bangun Ruang — Kelas 12 Lanjut.",33,"2026-10-08T09:24:41.627Z",{"id":1791,"subjectId":172,"levelId":17,"parentId":17,"slug":1792,"name":1793,"description":1794,"order":1795,"createdAt":1796,"updatedAt":1796},"demo-v2-topic-pemrograman-sd-1","demo-v2-sd-1","Algoritma: Urutan Perintah yang Jelas","Susun instruksi sederhana, lalu telusuri hasilnya selangkah demi selangkah.",100,"2026-10-08T10:03:56.954Z",{"id":1798,"subjectId":161,"levelId":71,"parentId":17,"slug":77,"name":1799,"description":1800,"order":1795,"createdAt":1801,"updatedAt":1801},"demo-v2-topic-matematika-sma-1","Fungsi kuadrat: akar, puncak, dan bentuk grafik","Menghubungkan bentuk umum, faktor, dan kuadrat sempurna untuk memahami parabola dan nilai optimum.","2026-10-08T10:03:56.485Z",{"id":1803,"subjectId":172,"levelId":71,"parentId":17,"slug":77,"name":1804,"description":1805,"order":1795,"createdAt":1806,"updatedAt":1806},"demo-v2-topic-pemrograman-sma-1","Fungsi: Memisahkan Masukan, Proses, dan Hasil","Buat fungsi Python yang bisa dipakai ulang dan bedakan return dari print.","2026-10-08T10:03:57.108Z",{"id":1808,"subjectId":20,"levelId":101,"parentId":17,"slug":1809,"name":1810,"description":1811,"order":1795,"createdAt":1812,"updatedAt":1812},"demo-v2-topic-fisika-smp-1","demo-v2-smp-1","Gerak Lurus: Jarak, Perpindahan, dan Grafik Posisi","Membedakan kelajuan dan kecepatan rata-rata serta membaca arti kemiringan grafik posisi terhadap waktu.","2026-10-08T10:03:56.729Z",{"id":76,"subjectId":20,"levelId":71,"parentId":17,"slug":77,"name":15,"description":16,"order":1795,"createdAt":1814,"updatedAt":1814},"2026-10-08T10:03:56.801Z",{"id":1816,"subjectId":20,"levelId":17,"parentId":17,"slug":1792,"name":1817,"description":1818,"order":1795,"createdAt":1819,"updatedAt":1819},"demo-v2-topic-fisika-sd-1","Mengukur Panjang dan Volume Benda","Membaca penggaris, memakai satuan baku, dan menghitung isi kubus melalui susunan kubus kecil.","2026-10-08T10:03:56.657Z",{"id":1821,"subjectId":172,"levelId":106,"parentId":17,"slug":156,"name":1822,"description":1823,"order":1795,"createdAt":1824,"updatedAt":1824},"demo-v2-topic-pemrograman-kuliah-1","Pencarian Linear, Set, dan Biaya Operasi","Bandingkan cara mencari anggota data melalui langkah yang benar-benar dikerjakan.","2026-10-08T10:03:57.182Z",{"id":1826,"subjectId":161,"levelId":101,"parentId":17,"slug":1809,"name":1827,"description":1828,"order":1795,"createdAt":1829,"updatedAt":1829},"demo-v2-topic-matematika-smp-1","Perbandingan senilai dan berbalik nilai","Memilih model dari besaran yang tetap: rasio tetap untuk senilai dan hasil kali tetap untuk berbalik nilai.","2026-10-08T10:03:56.412Z",{"id":1831,"subjectId":161,"levelId":106,"parentId":17,"slug":156,"name":1832,"description":1833,"order":1795,"createdAt":1834,"updatedAt":1834},"demo-v2-topic-matematika-kuliah-1","Turunan sebagai laju sesaat dan pendekatan lokal","Menurunkan fungsi dari limit hasil bagi selisih serta menghubungkan kemiringan, kecepatan, dan garis singgung.","2026-10-08T10:03:56.556Z",{"id":1836,"subjectId":172,"levelId":101,"parentId":17,"slug":1809,"name":1837,"description":1838,"order":1795,"createdAt":1839,"updatedAt":1839},"demo-v2-topic-pemrograman-smp-1","Variabel, Tipe Data, dan Keluaran Python","Simpan nilai dengan nama yang jelas dan bedakan angka dari teks.","2026-10-08T10:03:57.035Z",{"id":155,"subjectId":20,"levelId":106,"parentId":17,"slug":156,"name":146,"description":147,"order":1795,"createdAt":1841,"updatedAt":1841},"2026-10-08T10:03:56.874Z",{"id":1843,"subjectId":161,"levelId":71,"parentId":17,"slug":1844,"name":1845,"description":1846,"order":1847,"createdAt":1848,"updatedAt":1848},"demo-v2-topic-matematika-sma-2","demo-v2-sma-2","Eksponen dan logaritma: mencari pangkat yang belum diketahui","Membedakan kenaikan tetap dan faktor tetap, lalu membaca logaritma sebagai operasi balik eksponen.",101,"2026-10-08T10:03:56.507Z",{"id":1850,"subjectId":161,"levelId":101,"parentId":17,"slug":1851,"name":1852,"description":1853,"order":1847,"createdAt":1854,"updatedAt":1854},"demo-v2-topic-matematika-smp-2","demo-v2-smp-2","Fungsi linear: gradien dan titik potong","Membaca y = mx + b sebagai perubahan tetap, menghitung gradien dari dua titik, dan memeriksa grafik.","2026-10-08T10:03:56.434Z",{"id":1856,"subjectId":20,"levelId":17,"parentId":17,"slug":1857,"name":1858,"description":1859,"order":1847,"createdAt":1860,"updatedAt":1860},"demo-v2-topic-fisika-sd-2","demo-v2-sd-2","Gaya: Dorongan, Tarikan, dan Perubahan Gerak","Mengenali siapa yang memberikan gaya, arah gaya, dan perubahan gerak atau bentuk yang dapat diamati.","2026-10-08T10:03:56.679Z",{"id":1862,"subjectId":20,"levelId":71,"parentId":17,"slug":1844,"name":1863,"description":1864,"order":1847,"createdAt":1865,"updatedAt":1865},"demo-v2-topic-fisika-sma-2","Gerak Peluru: Dua Arah dengan Satu Waktu","Menguraikan kecepatan awal, menghitung waktu terbang, tinggi maksimum, dan jangkauan untuk model ideal.","2026-10-08T10:03:56.824Z",{"id":1867,"subjectId":161,"levelId":106,"parentId":17,"slug":141,"name":1868,"description":1869,"order":1847,"createdAt":1870,"updatedAt":1870},"demo-v2-topic-matematika-kuliah-2","Integral tentu: akumulasi dan luas bertanda","Menghubungkan jumlah Riemann, antiturunan, dan teorema dasar kalkulus tanpa menyamakan perpindahan dengan jarak.","2026-10-08T10:03:56.578Z",{"id":1872,"subjectId":172,"levelId":106,"parentId":17,"slug":141,"name":1873,"description":1874,"order":1847,"createdAt":1875,"updatedAt":1875},"demo-v2-topic-pemrograman-kuliah-2","Kelas dan Invarian pada Objek","Kelola keadaan dan perilaku bersama, lalu jaga agar objek selalu valid.","2026-10-08T10:03:57.206Z",{"id":1877,"subjectId":172,"levelId":71,"parentId":17,"slug":1844,"name":1878,"description":1879,"order":1847,"createdAt":1880,"updatedAt":1880},"demo-v2-topic-pemrograman-sma-2","List dan Dictionary untuk Mengolah Data","Pilih struktur data sesuai cara mengaksesnya dan hitung ringkasan data.","2026-10-08T10:03:57.131Z",{"id":1882,"subjectId":20,"levelId":101,"parentId":17,"slug":1851,"name":1883,"description":1884,"order":1847,"createdAt":1885,"updatedAt":1885},"demo-v2-topic-fisika-smp-2","Massa Jenis: Menghubungkan Massa dan Volume","Menghitung massa jenis, mengukur volume dengan perpindahan air, dan menjaga konsistensi satuan.","2026-10-08T10:03:56.750Z",{"id":140,"subjectId":20,"levelId":106,"parentId":17,"slug":141,"name":130,"description":131,"order":1847,"createdAt":1887,"updatedAt":1887},"2026-10-08T10:03:56.896Z",{"id":1889,"subjectId":172,"levelId":17,"parentId":17,"slug":1857,"name":1890,"description":1891,"order":1847,"createdAt":1892,"updatedAt":1892},"demo-v2-topic-pemrograman-sd-2","Pengulangan: Langkah yang Dikerjakan Berkali-kali","Kenali pola berulang dan hitung hasil tiap putaran tanpa kehilangan jejak.","2026-10-08T10:03:56.978Z",{"id":1894,"subjectId":172,"levelId":101,"parentId":17,"slug":1851,"name":1895,"description":1896,"order":1847,"createdAt":1897,"updatedAt":1897},"demo-v2-topic-pemrograman-smp-2","Percabangan Python dan Batas Keputusan","Tulis if, elif, dan else serta uji nilai di sekitar batas.","2026-10-08T10:03:57.057Z",{"id":1899,"subjectId":20,"levelId":71,"parentId":17,"slug":1900,"name":1901,"description":1902,"order":1903,"createdAt":1904,"updatedAt":1904},"demo-v2-topic-fisika-sma-3","demo-v2-sma-3","Hukum Ohm, Daya, dan Energi pada Resistor","Menghubungkan tegangan, arus, hambatan, dan energi listrik tanpa mencampurkan satuan volt, ampere, watt, dan joule.",102,"2026-10-08T10:03:56.846Z",{"id":1906,"subjectId":172,"levelId":71,"parentId":17,"slug":1900,"name":1907,"description":1908,"order":1903,"createdAt":1909,"updatedAt":1909},"demo-v2-topic-pemrograman-sma-3","Membaca Berkas dan Menangani Masukan Salah","Ubah baris teks menjadi angka dan tangani kesalahan yang bisa diperkirakan.","2026-10-08T10:03:57.153Z",{"id":1911,"subjectId":161,"levelId":71,"parentId":17,"slug":1900,"name":1912,"description":1913,"order":1903,"createdAt":1914,"updatedAt":1914},"demo-v2-topic-matematika-sma-3","Peluang: ruang sampel, kejadian, dan pengambilan bertahap","Menghitung peluang melalui hasil yang sama mungkin dan memahami pengaruh pengembalian pada pengambilan kedua.","2026-10-08T10:03:56.528Z",{"id":1916,"subjectId":172,"levelId":106,"parentId":17,"slug":125,"name":1917,"description":1918,"order":1903,"createdAt":1919,"updatedAt":1919},"demo-v2-topic-pemrograman-kuliah-3","Pengujian Otomatis dan Kasus Batas","Uji kontrak fungsi dengan contoh biasa, batas, dan masukan tidak sah.","2026-10-08T10:03:57.229Z",{"id":1921,"subjectId":172,"levelId":17,"parentId":17,"slug":1922,"name":1923,"description":1924,"order":1903,"createdAt":1925,"updatedAt":1925},"demo-v2-topic-pemrograman-sd-3","demo-v2-sd-3","Percabangan: Memilih Tindakan dengan Syarat","Gunakan pertanyaan ya atau tidak untuk menentukan tindakan yang tepat.","2026-10-08T10:03:57.006Z",{"id":1927,"subjectId":172,"levelId":101,"parentId":17,"slug":1928,"name":1929,"description":1930,"order":1903,"createdAt":1931,"updatedAt":1931},"demo-v2-topic-pemrograman-smp-3","demo-v2-smp-3","Perulangan for dan Akumulator","Hitung total data dengan jejak putaran yang dapat diperiksa.","2026-10-08T10:03:57.079Z",{"id":1933,"subjectId":20,"levelId":17,"parentId":17,"slug":1922,"name":1934,"description":1935,"order":1903,"createdAt":1936,"updatedAt":1936},"demo-v2-topic-fisika-sd-3","Suhu dan Perpindahan Kalor di Sekitar Kita","Membaca perubahan suhu dan membedakan konduksi, konveksi, serta radiasi melalui kejadian sehari-hari.","2026-10-08T10:03:56.700Z",{"id":1938,"subjectId":161,"levelId":101,"parentId":17,"slug":1928,"name":1939,"description":1940,"order":1903,"createdAt":1941,"updatedAt":1941},"demo-v2-topic-matematika-smp-3","Teorema Pythagoras dan jarak diagonal","Menentukan sisi segitiga siku-siku dengan kuadrat panjang, lalu memeriksa hasil melalui geometri dan satuan.","2026-10-08T10:03:56.456Z",{"id":124,"subjectId":20,"levelId":106,"parentId":17,"slug":125,"name":114,"description":115,"order":1903,"createdAt":1943,"updatedAt":1943},"2026-10-08T10:03:56.918Z",{"id":1945,"subjectId":20,"levelId":101,"parentId":17,"slug":1928,"name":1946,"description":1947,"order":1903,"createdAt":1948,"updatedAt":1948},"demo-v2-topic-fisika-smp-3","Usaha dan Energi: Memeriksa Perubahan dengan Joule","Menghitung usaha gaya searah atau berlawanan, energi gerak, dan perubahan energi ketika benda diangkat.","2026-10-08T10:03:56.772Z",{"id":1950,"subjectId":161,"levelId":106,"parentId":17,"slug":125,"name":1951,"description":1952,"order":1903,"createdAt":1953,"updatedAt":1953},"demo-v2-topic-matematika-kuliah-3","Vektor tiga dimensi dan hasil kali titik","Membaca komponen, menghitung panjang dan sudut, serta menafsirkan hasil kali titik sebagai keselarasan arah.","2026-10-08T10:03:56.615Z",[]]